【下载文档:  Python新手实现2048小游戏.txt 】

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Python新手实现2048小游戏
接触 Python 不久，看到很多人写2048，自己也捣鼓了一个，主要是熟悉Python语法。
程序使用Python3 写的，代码150行左右，基于控制台，方向键使用输入字符模拟。
演示图片
2048.py
# -*- coding:UTF-8 -*-
#! /usr/bin/python3
import random
v = [[0, 0, 0, 0],
[0, 0, 0, 0],
[0, 0, 0, 0],
[0, 0, 0, 0]]
def display(v, score):
'''显示界面
'''
print('{0:4} {1:4} {2:4} {3:4}'.format(v[0][0], v[0][1], v[0][2], v[0][3]))
print('{0:4} {1:4} {2:4} {3:4}'.format(v[1][0], v[1][1], v[1][2], v[1][3]))
print('{0:4} {1:4} {2:4} {3:4}'.format(v[2][0], v[2][1], v[2][2], v[2][3]))
print('{0:4} {1:4} {2:4} {3:4}'.format(v[3][0], v[3][1], v[3][2], v[3][3]), ' Total score: ', score)
def init(v):
'''随机分布网格值
'''
for i in range(4):
v[i] = [random.choice([0, 0, 0, 2, 2, 4]) for x in range(4)]
def align(vList, direction):
'''对齐非零的数字
direction == 'left'：向左对齐，例如[8,0,0,2]左对齐后[8,2,0,0]
direction == 'right'：向右对齐，例如[8,0,0,2]右对齐后[0,0,8,2]
'''
# 移除列表中的0
for i in range(vList.count(0)):
vList.remove(0)
# 被移除的0
zeros = [0 for x in range(4 - len(vList))]
# 在非0数字的一侧补充0
if direction == 'left':
vList.extend(zeros)
else:
vList[:0] = zeros
def addSame(vList, direction):
'''在列表查找相同且相邻的数字相加, 找到符合条件的返回True，否则返回False,同时还返回增加的分数
direction == 'left':从右向左查找，找到相同且相邻的两个数字，左侧数字翻倍，右侧数字置0
direction == 'right':从左向右查找，找到相同且相邻的两个数字，右侧数字翻倍，左侧数字置0
'''
score = 0
if direction == 'left':
for i in [0, 1, 2]:
if vList[i] == vList[i+1] != 0:
vList[i] *= 2
vList[i+1] = 0
score += vList[i]
return {'bool':True, 'score':score}
else:
for i in [3, 2, 1]:
if vList[i] == vList[i-1] != 0:
vList[i-1] *= 2
vList[i] = 0
score += vList[i-1]
return {'bool':True, 'score':score}
return {'bool':False, 'score':score}
def handle(vList, direction):
'''处理一行（列）中的数据，得到最终的该行（列）的数字状态值, 返回得分
vList: 列表结构，存储了一行（列）中的数据
direction: 移动方向,向上和向左都使用方向'left'，向右和向下都使用'right'
'''
totalScore = 0
align(vList, direction)
result = addSame(vList, direction)
while result['bool'] == True:
totalScore += result['score']
align(vList, direction)
result = addSame(vList, direction)
return totalScore
def operation(v):
'''根据移动方向重新计算矩阵状态值，并记录得分
'''
totalScore = 0
gameOver = False
direction = 'left'
op = input('operator:')
if op in ['a', 'A']: # 向左移动
direction = 'left'
for row in range(4):
totalScore += handle(v[row], direction)
elif op in ['d', 'D']: # 向右移动
direction = 'right'
for row in range(4):
totalScore += handle(v[row], direction)
elif op in ['w', 'W']: # 向上移动
direction = 'left'
for col in range(4):
# 将矩阵中一列复制到一个列表中然后处理
vList = [v[row][col] for row in range(4)]
totalScore += handle(vList, direction)
# 从处理后的列表中的数字覆盖原来矩阵中的值
for row in range(4):
v[row][col] = vList[row]
elif op in ['s', 'S']: # 向下移动
direction = 'right'
for col in range(4):
# 同上
vList = [v[row][col] for row in range(4)]
totalScore += handle(vList, direction)
for row in range(4):
v[row][col] = vList[row]
else:
print('Invalid input, please enter a charactor in [W, S, A, D] or the lower')
return {'gameOver':gameOver, 'score':totalScore}
# 统计空白区域数目 N
N = 0
for q in v:
N += q.count(0)
# 不存在剩余的空白区域时，游戏结束
if N == 0:
gameOver = True
return {'gameOver':gameOver, 'score':totalScore}
# 按2和4出现的几率为3/1来产生随机数2和4
num = random.choice([2, 2, 2, 4])
# 产生随机数k，上一步产生的2或4将被填到第k个空白区域
k = random.randrange(1, N+1)
n = 0
for i in range(4):
for j in range(4):
if v[i][j] == 0:
n += 1
if n == k:
v[i][j] = num
break
return {'gameOver':gameOver, 'score':totalScore}
init(v)
score = 0
print('Input：W(Up) S(Down) A(Left) D(Right), press .')
while True:
display(v, score)
result = operation(v)
if result['gameOver'] == True:
print('Game Over, You failed!')
print('Your total score:', score)
else:
score += result['score']
if score >= 2048:
print('Game Over, You Win!!!')
print('Your total score:', score)
以上所述就是本文给大家分享的全部代码了，希望能够对大家学习Python有所帮助。