Python新手实现2048小游戏


            接触 Python 不久，看到很多人写2048，自己也捣鼓了一个，主要是熟悉Python语法。

程序使用Python3 写的，代码150行左右，基于控制台，方向键使用输入字符模拟。

演示图片



2048.py





# -*- coding:UTF-8 -*-

#! /usr/bin/python3

 

import random

 

v = [[0, 0, 0, 0],

   [0, 0, 0, 0],

   [0, 0, 0, 0],

   [0, 0, 0, 0]]

 

def display(v, score):

    '''显示界面

 

    '''

    print('{0:4} {1:4} {2:4} {3:4}'.format(v[0][0], v[0][1], v[0][2], v[0][3]))

    print('{0:4} {1:4} {2:4} {3:4}'.format(v[1][0], v[1][1], v[1][2], v[1][3]))

    print('{0:4} {1:4} {2:4} {3:4}'.format(v[2][0], v[2][1], v[2][2], v[2][3]))

    print('{0:4} {1:4} {2:4} {3:4}'.format(v[3][0], v[3][1], v[3][2], v[3][3]), '  Total score: ', score)

 

def init(v):

    '''随机分布网格值

     

    '''

    for i in range(4):

        v[i] = [random.choice([0, 0, 0, 2, 2, 4]) for x in range(4)]

 

def align(vList, direction):

    '''对齐非零的数字

 

    direction == 'left'：向左对齐，例如[8,0,0,2]左对齐后[8,2,0,0]

    direction == 'right'：向右对齐，例如[8,0,0,2]右对齐后[0,0,8,2]

    '''

 

    # 移除列表中的0

    for i in range(vList.count(0)):

        vList.remove(0)

    # 被移除的0

    zeros = [0 for x in range(4 - len(vList))]

    # 在非0数字的一侧补充0

    if direction == 'left':

        vList.extend(zeros)

    else:

        vList[:0] = zeros

     

def addSame(vList, direction):

    '''在列表查找相同且相邻的数字相加, 找到符合条件的返回True，否则返回False,同时还返回增加的分数

     

    direction == 'left':从右向左查找，找到相同且相邻的两个数字，左侧数字翻倍，右侧数字置0

    direction == 'right':从左向右查找，找到相同且相邻的两个数字，右侧数字翻倍，左侧数字置0

    '''

    score = 0

    if direction == 'left':

        for i in [0, 1, 2]:

            if vList[i] == vList[i+1] != 0: 

                vList[i] *= 2

                vList[i+1] = 0

                score += vList[i]

                return {'bool':True, 'score':score}

    else:

        for i in [3, 2, 1]:

            if vList[i] == vList[i-1] != 0:

                vList[i-1] *= 2

                vList[i] = 0

                score += vList[i-1]

                return {'bool':True, 'score':score}

    return {'bool':False, 'score':score}

 

def handle(vList, direction):

    '''处理一行（列）中的数据，得到最终的该行（列）的数字状态值, 返回得分

 

    vList: 列表结构，存储了一行（列）中的数据

    direction: 移动方向,向上和向左都使用方向'left'，向右和向下都使用'right'

    '''

    totalScore = 0

    align(vList, direction)

    result = addSame(vList, direction)

    while result['bool'] == True:

        totalScore += result['score']

        align(vList, direction)

        result = addSame(vList, direction)

    return totalScore

     

 

def operation(v):

    '''根据移动方向重新计算矩阵状态值，并记录得分

    '''

    totalScore = 0

    gameOver = False

    direction = 'left'

    op = input('operator:')

    if op in ['a', 'A']:  # 向左移动

        direction = 'left'

        for row in range(4):

            totalScore += handle(v[row], direction)

    elif op in ['d', 'D']: # 向右移动

        direction = 'right'

        for row in range(4):

            totalScore += handle(v[row], direction)

    elif op in ['w', 'W']: # 向上移动

        direction = 'left'

        for col in range(4):

            # 将矩阵中一列复制到一个列表中然后处理

            vList = [v[row][col] for row in range(4)]

            totalScore += handle(vList, direction)

            # 从处理后的列表中的数字覆盖原来矩阵中的值

            for row in range(4):

                v[row][col] = vList[row]

    elif op in ['s', 'S']: # 向下移动

        direction = 'right'

        for col in range(4):

            # 同上

            vList = [v[row][col] for row in range(4)]

            totalScore += handle(vList, direction)

            for row in range(4):

                v[row][col] = vList[row]

    else:

        print('Invalid input, please enter a charactor in [W, S, A, D] or the lower')

        return {'gameOver':gameOver, 'score':totalScore}

 

    # 统计空白区域数目 N

    N = 0

    for q in v:

      N += q.count(0)

    # 不存在剩余的空白区域时，游戏结束

    if N == 0:

        gameOver = True

        return {'gameOver':gameOver, 'score':totalScore}

 

    # 按2和4出现的几率为3/1来产生随机数2和4

    num = random.choice([2, 2, 2, 4]) 

    # 产生随机数k，上一步产生的2或4将被填到第k个空白区域

    k = random.randrange(1, N+1)

    n = 0

    for i in range(4):

        for j in range(4):

            if v[i][j] == 0:

                n += 1

                if n == k:

                    v[i][j] = num

                    break

 

    return {'gameOver':gameOver, 'score':totalScore}

 

init(v)

score = 0

print('Input：W(Up) S(Down) A(Left) D(Right), press <CR>.')

while True:

    display(v, score)

    result = operation(v)

    if result['gameOver'] == True:

        print('Game Over, You failed!')

        print('Your total score:', score)

    else:

        score += result['score']

        if score >= 2048:

            print('Game Over, You Win!!!')

            print('Your total score:', score)



以上所述就是本文给大家分享的全部代码了，希望能够对大家学习Python有所帮助。