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PHP获取一年有几周以及每周开始日期和结束日期

来源:中文源码网    浏览:221 次    日期:2024-04-28 07:48:58
【下载文档:  PHP获取一年有几周以及每周开始日期和结束日期.txt 】


PHP获取一年有几周以及每周开始日期和结束日期
最近接了一个项目,其中有一需求是用php获取一年有几周以及每周开始日期和接触日期。在网上找些资料没有合适的,于是自己做了一份,下面通过两种方式实现PHP获取一年有几周以及每周开始日期和结束日期
代码一:
header("Content-type:text/html;charset=utf-8");
date_default_timezone_set("Asia/Shanghai");
$year = (int)$_GET['year'];
$week = (int)$_GET['week'];
$weeks = date("W", mktime(0, 0, 0, 12, 28, $year));
echo $year . '年一共有' . $weeks . '周
';
if ($week > $weeks || $week <= 0)
{
$week = 1;
}
if ($week < 10)
{
$week = '0' . $week;
}
$timestamp['start'] = strtotime($year . 'W' . $week);
$timestamp['end'] = strtotime('+1 week -1 day', $timestamp['start']);
echo $year . '年第' . $week . '周开始时间戳:' . $timestamp['start'] . '
';
echo $year . '年第' . $week . '周结束时间戳:' . $timestamp['end'] . '
';
echo $year . '年第' . $week . '周开始日期:' . date("Y-m-d", $timestamp['start']) . '
';
echo $year . '年第' . $week . '周结束日期:' . date("Y-m-d", $timestamp['end']);
?>
代码二:
header("Content-type:text/html;charset=utf-8");
function getIsoWeeksInYear($year)
{
$date = new DateTime;
$date->setISODate($year, 53);
return ($date->format("W") === "53" ? 53 : 52);
}
function weekday($custom_date)
{
$week_start = date('d-m-Y', strtotime('this week monday', $custom_date));
$week_end = date('d-m-Y', strtotime('this week sunday', $custom_date));
$week_array[0] = $week_start;
$week_array[1] = $week_end;
return $week_array;
}
echo '
Weeks in 2013
' . getIsoWeeksInYear(2013);
$weekday = weekday(strtotime(date('d-m-Y', strtotime('5-8-2013'))));
echo '
10-8-2013';
echo '
Start: ' . $weekday[0];
echo '
End: ' . $weekday[1];
?>
以上本文的全部内容,希望对大家学习PHP获取一年有几周以及每周开始日期和结束日期,有所帮助。

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