PHP获取一年有几周以及每周开始日期和结束日期


            最近接了一个项目，其中有一需求是用php获取一年有几周以及每周开始日期和接触日期。在网上找些资料没有合适的，于是自己做了一份，下面通过两种方式实现PHP获取一年有几周以及每周开始日期和结束日期

代码一：





<?php

header("Content-type:text/html;charset=utf-8");

date_default_timezone_set("Asia/Shanghai");

$year = (int)$_GET['year'];

$week = (int)$_GET['week'];

$weeks = date("W", mktime(0, 0, 0, 12, 28, $year));

echo $year . '年一共有' . $weeks . '周<br />';

if ($week > $weeks || $week <= 0)

{

 $week = 1;

}

if ($week < 10)

{

 $week = '0' . $week;

}

$timestamp['start'] = strtotime($year . 'W' . $week);

$timestamp['end'] = strtotime('+1 week -1 day', $timestamp['start']);

echo $year . '年第' . $week . '周开始时间戳：' . $timestamp['start'] . '<br />';

echo $year . '年第' . $week . '周结束时间戳：' . $timestamp['end'] . '<br />';

echo $year . '年第' . $week . '周开始日期：' . date("Y-m-d", $timestamp['start']) . '<br />';

echo $year . '年第' . $week . '周结束日期：' . date("Y-m-d", $timestamp['end']);

?>



代码二：





<?php

header("Content-type:text/html;charset=utf-8");

function getIsoWeeksInYear($year)

{

 $date = new DateTime;

 $date->setISODate($year, 53);

 return ($date->format("W") === "53" ? 53 : 52);

}

function weekday($custom_date)

{

 $week_start = date('d-m-Y', strtotime('this week monday', $custom_date));

 $week_end = date('d-m-Y', strtotime('this week sunday', $custom_date));

 $week_array[0] = $week_start;

 $week_array[1] = $week_end;

 return $week_array;

}

echo '<br> Weeks in 2013<br>' . getIsoWeeksInYear(2013);

$weekday = weekday(strtotime(date('d-m-Y', strtotime('5-8-2013'))));

echo '<br> 10-8-2013';

echo '<br>Start: ' . $weekday[0];

echo '<br>End: ' . $weekday[1];

?>





以上本文的全部内容，希望对大家学习PHP获取一年有几周以及每周开始日期和结束日期，有所帮助。