PHP将二维数组某一个字段相同的数组合并起来的方法 本文实例讲述了PHP将二维数组某一个字段相同的数组合并起来的方法。分享给大家供大家参考,具体如下: 例子: array(3) { [0]=> array(16) { ["id"]=> string(2) "42" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1443927600" ["createtime"]=> string(10) "1443880619" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月04日" ["date"]=> string(6) "周日" ["uname"]=> NULL ["album"]=> string(0) "" } [1]=> array(16) { ["id"]=> string(2) "40" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359600" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } [2]=> array(16) { ["id"]=> string(2) "43" ["uid"]=> string(1) "2" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359620" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } } 现在想要对这个二维数组下的元素,time相同的合并到同一数组下。想要的效果为: array(2) { ["10月04日"]=> array(1) { [0]=> array(16) { ["id"]=> string(2) "42" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1443927600" ["createtime"]=> string(10) "1443880619" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月04日" ["date"]=> string(6) "周日" ["uname"]=> NULL ["album"]=> string(0) "" } } ["10月09日"]=> array(2) { [0]=> array(16) { ["id"]=> string(2) "40" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359600" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } [1]=> array(16) { ["id"]=> string(2) "43" ["uid"]=> string(1) "2" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359620" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } } } 那么。。。代码很简单,没有想象的那么复杂,想要的结果是个三维数组 $result 为原二维数组 $res = array(); //想要的结果 foreach ($result as $k => $v) { $res[$v['time']][] = $v; } 更多关于PHP相关内容感兴趣的读者可查看本站专题:《php面向对象程序设计入门教程》、《php字符串(string)用法总结》、《php+mysql数据库操作入门教程》及《php常见数据库操作技巧汇总》 希望本文所述对大家PHP程序设计有所帮助。