PHP实现的mysql主从数据库状态检测功能示例


            本文实例讲述了PHP实现的mysql主从数据库状态检测功能。分享给大家供大家参考，具体如下：

实例：





<?php

/**

 * 检测多个主从数据库是否挂掉

 * 建立从数据库$slave_db的二维数组，内容包含每个从服务器的配置数据

 */

header("Content-Type: text/html; charset=utf-8");

set_time_limit(0);

$slave_db = array(

  'db1'=>array(

    'hostname' => '127.0.0.1',

    'port' => 3306,

    'database' => 'test',

    'username' => 'root',

    'password' => '111111',

    'charset' => 'utf8',

  ),

  'db2'=>array(

    'hostname' => '127.0.0.2',

    'port' => 3306,

    'database' => 'test',

    'username' => 'root',

    'password' => '111111',

    'charset' => 'utf8',

  ),

);

$content = '';

foreach ($slave_db as $db_key) {

  $host = $db_key['hostname'];

  $port = $db_key['port'];

  $db_user = $db_key['username'];

  $db_pass = $db_key['password'];

  $slave_link = mysql_connect($host,$db_user,$db_pass);

  if(mysql_errno()) {

    $content .= "从数据库( $host )无法连接 ！ <br/>";

    $content .= mysql_error() . "<br/>";

    continue;

  }

  $sql = "show slave status";

  $result = mysql_query($sql, $slave_link);

  $row = mysql_fetch_assoc($result);

  $Slave_IO_Running = $row['Slave_IO_Running'];

  $Slave_SQL_Running = $row['Slave_SQL_Running'];

  if ('Yes' == $Slave_IO_Running && 'Yes' == $Slave_SQL_Running) {

  } else {

    $content .= "从数据库( $host )挂掉了！ <br/>";

  }

  mysql_free_result($result);

  mysql_close($slave_link);

}

//若报错信息不为空，发送报错邮件

if(!empty($content)) {

  $title = '主从数据库状态检测报错 ';

  $content = date("Y-m-d H:i:s",time()) . "<br/>" . $content;

  $sendurl = "http://localhost/api.ftrend.com/test.php?title=".$title."&content=".$content;

  $result = file_get_contents($sendurl);

  if('ok' != $result) {

    $message = date("Y-m-d H:i:s",time()).'slaveStatus.php主从数据库状态检测报错,邮件发送失败!'."\n";

    $content = str_replace("<br/>", "\n", $content);

    $message .= $content;

    error_log($message,3,"error.log");

  }

}











<?php

$title = $_GET['title'];

$content = $_GET['content'];

$content = str_replace("<br/>", "\n", $content);

error_log($title."\n",3,'error.log');

error_log($content."\n",3,'error.log');

echo 'ok';







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