Python实现的简单算术游戏实例


            本文实例讲述了Python实现的简单算术游戏。分享给大家供大家参考。具体实现方法如下：





#!/usr/bin/env python

from operator import add, sub 

from random import randint, choice

ops = {'+': add, '-':sub}

#定义一个字典

MAXTRIES = 2 

def doprob():

  op = choice('+-')

  #用choice从'+-'中随意选择操作符 

  nums = [randint(1,10) for i in range(2)]

  #用randint(1,10)随机生成一个1到10的数,随机两次使用range(2) 

  nums.sort(reverse=True)

  #按升序排序

  ans = ops[op](*nums)

  #利用函数

  pr = '%d %s %d = ' % (nums[0], op, nums[1])

  oops = 0 

  #oops用来计算failure测试,当三次时自动给出答案

  while True:

    try:

      if int(raw_input(pr)) == ans:

        print 'correct'

        break

      if oops == MAXTRIES:

        print 'answer\n %s%d' % (pr, ans)

        break

      else:

        print 'incorrect... try again'

        oops += 1

    except (KeyboardInterrupt, EOFError, ValueError):

      print 'invalid ipnut... try again'

def main():

  while True:

    doprob()

    try:

      opt = raw_input('Again? [y]').lower()

      if opt and opt[0] == 'n':

        break

    except (KeyboardInterrupt, EOFError):

      break

if __name__ == '__main__':

  main()







运行结果如下：





8 - 1 = 7

correct

Again? [y]y

7 - 1 = 6

correct

Again? [y]y

9 + 4 = 0

incorrect... try again

9 + 4 = 







希望本文所述对大家的Python程序设计有所帮助。