python3判断url链接是否为404的方法


            本文实例为大家分享了python3判断url链接是否为404的具体代码，供大家参考，具体内容如下







import pymysql

import threading

import time

import urllib

import requests

 

# 打开数据库连接

db = pymysql.connect("192.168.0.*", "username", "password", "databasename")

# 使用 cursor() 方法创建一个游标对象 cursor

cursor = db.cursor()

# SQL 查询语句

sql = "SELECT sku,url_6 FROM url_new where flag_6 is null and url_6<>'' "

  # 执行SQL语句

cursor.execute(sql)

  # 获取所有记录列表

results = cursor.fetchall()

num = 0

for row in results:

  sku = row[0]

  url = row[1]

  html = requests.head(url) # 用head方法去请求资源头

  re=html.status_code

  num = num + 1

  print(num,re)

  if re == 200:

    sql_2 = "UPDATE url_new SET flag_6 = 0 WHERE sku = '%s'" % sku

    try:

      # 执行SQL语句

      cursor.execute(sql_2)

      #print(cursor.rowcount)

    except Exception as e:

      print(e)

      conn.rollback()

  if re == 404:

    sql_3 = "UPDATE url_new SET flag_6 = 1 WHERE sku = '%s'" % sku

    try:

      # 执行SQL语句

      cursor.execute(sql_3)

      print(cursor.rowcount)

    except Exception as e:

      print(e)

      conn.rollback()

  db.commit()

db.close()



以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持中文源码网。