python抽取指定url页面的title方法 今天简单使用了一下python的re模块和lxml模块,分别利用的它们提供的正则表达式和xpath来解析页面源码从中提取所需的title,xpath在完成这样的小任务上效率非常好,在这里之所以又使用了一下正则表达式是因为xpath在处理一些特殊的页面的时候会出现乱码的情况,当然这不是xpath的原因,而是页面本身编码,跟utf-8转码之间有冲突所致,这里看代码: # !/usr/bin/python #-*-coding:utf-8-*- ''' 功能:抽取指定url的页面内容中的title ''' import re import chardet import urllib from lxml import etree def utf8_transfer(strs): ''' utf8编码转换 ''' try: if isinstance(strs, unicode): strs = strs.encode('utf-8') elif chardet.detect(strs)['encoding'] == 'GB2312': strs = strs.decode("gb2312", 'ignore').encode('utf-8') elif chardet.detect(strs)['encoding'] == 'utf-8': strs = strs.decode('utf-8', 'ignore').encode('utf-8') except Exception, e: print 'utf8_transfer error', strs, e return strs def get_title_xpath(Html): ''' 用xpath抽取网页Title ''' Html = utf8_transfer(Html) Html_encoding = chardet.detect(Html)['encoding'] page = etree.HTML(Html, parser=etree.HTMLParser(encoding=Html_encoding)) title = page.xpath('/html/head/title/text()') try: title = title[0].strip() except IndexError: print 'Nothing' print title def get_title(Html): ''' 用re抽取网页Title ''' Html = utf8_transfer(Html) compile_rule = ur'